Question

two chords ab and CD intersect at P with Centre O if angle AOC = 110degree and Angle APC equals to 95 degree find angle BOC​

Answer 1

Step-by-step explanation:

the three angles form exterior and interior pair of angles

so AOC = APC + BOC

110= 95 + BOC

BOC = 15 DEGREE

it was better to upload diagram as well

Answer 2

To find ∠BOC

Step-by-step explanation:

The angles∠AOC, ∠APC  and ∠BOC  form exterior and interior pair of angles

As we know Exterior angle = Sum of 2 interior angles

  Therefore we get,

∠ AOC = ∠APC + ∠BOC

Now put the values from the given question.

According to the question we get:

Putting the values of ∠ AOC =110° and ∠APC = 95° we get,

110°= 95° + ∠BOC

Thus solving the equation we get

∠BOC = 15°