Question

two chords AB and CD intersect each other at the point P. Prove that ∆APC~∆ADP​

Answer 1

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Answer 2

Proved that, $\therefore\bigtriangleup APC \simeq \bigtriangleup DPB$

Explanation:

According to the attached figure,

In $\bigtriangleup DPB$ and $\bigtriangleup APC$

Vertically opposite angles are equal

$\angle DPB = \angle APC$

Angles on the same segement of a circle are equal,

$\angle BDP = \angle CAP$

$\therefore\bigtriangleup APC \simeq \bigtriangleup DPB$

Proved it.