Question

Two chords, KL and MN of a circle intersect at an external point J. If KL = 15 cm. L J = 5cm, MN= 21 cm and NJ = 4 cm, the ratio of the area of the quadrilateral KLNM to the area of the triangle JKM will be ?
a) 24/25 b) 22/25 c) 17/20 d) 19/20

Answer 1

24/25 is your answer

Answer 2

$\huge{hey.. dear!!}$


SOLUTION=>

Angle KJM is a

Area JLN=1/2(5)(4)sina =10sina

Area JKM=1/2(20)(25)sina=250sina

Area KLNM=1/2(20)(25)sina - 1/2(5)(4)sina

=240sina

Ratio=240/250

24:25



so, option (a ) is correct ✅

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hope its hlp uh.....


$Sumit Tiwari from Azamgarh(up)$