Two circies are drawn with sides AB and AC of a triangle ABC as diameters. The circles intersect at a
point D. If AB = 5 cm, D =3 cmn and AC = 6 cm, find BC
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Step-by-step explanation:
by pythagorastheorem,
in triangle ABD
AD*AD=AB*AB - BD*BD.
AD*AD=5*5 - 3*3.
AD*AD=25 - 9
AD=root of 16= 4
AD=4cm
in triangle ADC
DC*DC=AC*AC - AD*AD.
DC*DC=6*6 - 4*4.
DC*DC=36 - 16
DC= root of 20
which is 3cm+root 20
thus ,BC= 3+root of 20
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