Math, asked by bpiskunowicz25, 11 months ago

Two circles are drawn inside a rectangle so their circumferences touch each other and three sides of the rectangle. If the areas of the circles are 8.3cm2 (squared) each, calculate the area of the rectangle.

Answers

Answered by Wynatt
28

Answer:

area of a circle=8.3cm²

area of the circle=(22/7)r²

=>8.3=(22/7)r²

=>(8.3×7)/22=r²

=>58.1/22=r²

=>2.64=r²

=>r=1.62cm

two circles are connected by their circumference and area also same

hence, diameter of one circle =half length of rectangle and breath = diameter of a circle.

hence, length=4r=6.5cm and breath=3.25cm

hence , area of a rectangle = l×b

area= 6.5×3.5

=>area=22.75cm²

Answered by RvChaudharY50
45

Given :-

  • 2 circle inside a Rectangle , such that, their circumferences touch each other and three sides of the rectangle.
  • Area of Each Circle = 8.3cm² .

To Find :-

  • Area of Rectangle ?

Solution :-

Area of Circle = 3.14 * r²

→ 3.14 * r² = 8.3

→ r² = 2.64

→ r = 1.6cm (Approx).

So,

diameter of Each circle = 1.6 * 2 = 3.2 cm.

Now,

Length of Rectangle =sum of Diameter of Both circles

Breadth of rectangle = Diameter of circle

So ,

Length = 3.2 + 3.2 = 6.4 cm.

Breadth = 3.2cm.

→ Area of Rectangle = Length * breadth = 6.4 * 3.2 = 20.48cm² (Approx). (Ans).

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