Question

Two circles of radii 20 cm and 37 cm intersect in A
and B. If O, and O. are their centres and AB= 24 cm
then the distance 0, 0, is equal to
(a) 44 cm
(b) 51 cm
(c) 40.5 cm
(d) 45 cm
​

Answer 1

Step-by-step explanation:

C is the mid-point of AB so that AC=12

AO

1

=37 and AO

2

=20 .....(Radii of circles)

Using Pythagoras theorem, we get

CO

1

=

37

2

−12

2

=35

CO

2

=

20

2

−12

2

=16

∴O

1

O

2

=35+16=51

option B is correct

Answer 2

Step-by-step explanation:

\sum\limits_{i=1}^n x_i = x_1 + x_2 + \dots + x_n

i = index of summation

n = upper limit of summation\sum\limits_{i=1}^n x_i = x_1 + x_2 + \dots + x_n

i = index of summation

n = upper limit of summation.