Question

two circles touch each other internally their radii are 2 and 3 cm find the length of the chord of the outer circle which touches the inner circle

Answer 1

Answer:

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Step-by-step explanation:

O′A=3cm  

OA=2cm

O′D=3cm

O′B=1cm

In△BDO

O′D2=BD^2+BO′^2

BD^2=(3)^2−(1)^2

BD^2=9−1

BD^2=8,    BD=2$\sqrt{2$

∴DE=2×BD

DE=×2$\sqrt{2}$

DE=4$\sqrt{2$