two circles touch externally the sum of their area is 58pie and the distance between their centre is 10 cm find radii of each circle
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Answered by
58
let the radii of the be Rcm and rcm let C1 and C2 be the centre of the 2 circle, then
C1c2=R+r
R+r =10cm……………(X)
given, the sum of their area =58pi
piR^2+Pir^2=58pi
R^2+r^2=58 [pi get cancelled ]
(R+r) ^2=58……………(1)
R^2+R^2+2Rr =58
(R+r)^2=58+2Rr
10^2=58+2Rr
100-58=2Rr
2Rr =42
Rr =21
R=21/r
putting it in equation 1
(21/r)^2+r^2=58
r^4+441=58r^2
r^4-58r^2+441=0
(r^2-49) (r^2-9)=0
r^2=49,9
r=7,3
putting the value of r in equation X, we have
R=3,7
therefore the radii of the circles are 7m and 3cm respectively.
C1c2=R+r
R+r =10cm……………(X)
given, the sum of their area =58pi
piR^2+Pir^2=58pi
R^2+r^2=58 [pi get cancelled ]
(R+r) ^2=58……………(1)
R^2+R^2+2Rr =58
(R+r)^2=58+2Rr
10^2=58+2Rr
100-58=2Rr
2Rr =42
Rr =21
R=21/r
putting it in equation 1
(21/r)^2+r^2=58
r^4+441=58r^2
r^4-58r^2+441=0
(r^2-49) (r^2-9)=0
r^2=49,9
r=7,3
putting the value of r in equation X, we have
R=3,7
therefore the radii of the circles are 7m and 3cm respectively.
Answered by
33
Answer:
Step-by-step explanation:
let the radii of the be Rcm and rcm let C1 and C2 be the centre of the 2 circle, then
C1c2=R+r
R+r =10cm……………(X)
given, the sum of their area =58pi
piR^2+Pir^2=58pi
R^2+r^2=58 [pi get cancelled ]
(R+r) ^2=58……………(1)
R^2+R^2+2Rr =58
(R+r)^2=58+2Rr
10^2=58+2Rr
100-58=2Rr
2Rr =42
Rr =21
R=21/r
putting it in equation 1
(21/r)^2+r^2=58
r^4+441=58r^2
r^4-58r^2+441=0
(r^2-49) (r^2-9)=0
r^2=49,9
r=7,3
putting the value of r in equation X, we have
R=3,7
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