two circles touch externally the sum of their areas is 130π square cm and the distance between the centre is 14 cm find the radius of the circle
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Solution:
Since the given circles touch externally, we have
sum of their radii = distance between their centres = 14 cm.
Let the radii of the given circles be x cm and (14 - x) cm.
Sum of their areas = [πx² + π(14 - x)²] cm²
.°. πx² + π(14 - x)² = 130π
→ x² + (14 - x)² = 130
→ 2x² - 28x + 66 = 0
→ x² - 14x + 33 = 0
→ (x-11)(x-3) = 0
→ x - 11 = 0 or x - 3 = 0
⇒x = 11 or x = 3.
Now, x = 11
→ (14- x) = (14-11) = 3.
And, x = 3 (14-x) = (14-3) = 11.
Hence, the radii of the given circles are 11 cm and 3 cm.
Answer:
- the radius of the circle are 11 cm and 3 cm.
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