two circles touches each other externally sum of their areas is 149π cm^2 & distance between their centers is 17 cm find the radii of the circle
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Answered by
2
Let the radius of one circle be x.
Area of 1st circle = pix^2 ------ (1)
Then the radius of another circle will be 17 - x.
Area of the second circle = pi(17 - x)^2. ------- (2)
Now,
Given that Sum of their areas = 149pi.
pix^2 + pi(17 - x)^2 = 149pi
pix^2 + pi(289 - 34x + x^2) = 149pi
x^2 + 289 - 34x + x^2 = 149
2x^2 - 34x + 140 = 0
x^2 - 17x + 70 = 0
x^2 - 10x - 7x + 70 = 0
x(x - 10) - 7(x - 10) = 0
(x - 7) = 0, (x - 10) = 0
x = 7,10.
Therefore the radii of the two circles are 10cm and 7cm.
Hope this helps!
Area of 1st circle = pix^2 ------ (1)
Then the radius of another circle will be 17 - x.
Area of the second circle = pi(17 - x)^2. ------- (2)
Now,
Given that Sum of their areas = 149pi.
pix^2 + pi(17 - x)^2 = 149pi
pix^2 + pi(289 - 34x + x^2) = 149pi
x^2 + 289 - 34x + x^2 = 149
2x^2 - 34x + 140 = 0
x^2 - 17x + 70 = 0
x^2 - 10x - 7x + 70 = 0
x(x - 10) - 7(x - 10) = 0
(x - 7) = 0, (x - 10) = 0
x = 7,10.
Therefore the radii of the two circles are 10cm and 7cm.
Hope this helps!
siddhartharao77:
If possible brainliest it.
Answered by
0
let one of the radii be x then the other will be 17-x
so
area of circle 1 +area of cicle 2 =149 pi
pi r1^2 + pi r2^2 =pi 149
x^2 + (17-x)^2 = 149
by doing the calculation
x^2 + 17^2 - 2*17x + x^2 =149
becomes
2x^2 + 289 - 34x = 149
on dividing 2
x^2 - 17x + 70
by splitting the middle term we will get
x=7,10
if x= 10 , 17-x= 7
if x =7 , 17-x=10
so
area of circle 1 +area of cicle 2 =149 pi
pi r1^2 + pi r2^2 =pi 149
x^2 + (17-x)^2 = 149
by doing the calculation
x^2 + 17^2 - 2*17x + x^2 =149
becomes
2x^2 + 289 - 34x = 149
on dividing 2
x^2 - 17x + 70
by splitting the middle term we will get
x=7,10
if x= 10 , 17-x= 7
if x =7 , 17-x=10
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