Two circles with a radius of 4 cm and 15 cm intersect
Externally touched. What is the length of their simple common tangent?
Answers
Answered by
1
Answer:
15+4=19 so 19 is tje answer
Answered by
0
The length of the tangent is = √d^2-(r1-r2)^2
d= distance between centers of circles= 15+4= 19cm
√(19)^2-(15-4)^2 === √-102 ====
== 10.099cm
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