Question

two circles with centers 0 AND O' OF RADIUS 3 CM AND 4CM RESPECTIVELY INTERSECT AT TWO POINTS P AMD Q SUCH THAT OP AND O'P ARE TANGENTS TO THE TWO CIRCLES.FIND THE LENGTH OF COMMON CHORD PQ

Answer 1

XP=HALF OF The​ CHORD =H
OX=B
XO`=5-B
OXP IS RIGHT ANGLE TRIANGLE
OX^2+XP^2=OP^2
B^2+H^2=9
H^2=9-B^2-------(1)
O`XP IS TRIANGLE
O`X^2+XP^2=OP^2
(5-B)^2+H^2=16
25+B^2-10B+9-B^2=16
-10B=-18
B=1.8
SUB B VALUE IN (1)
B^2=3.24
H^2=9-3.24
H^2=5.76
H=2.4
total length of chord =2*H=4.8

Answer 2

answer in image OK friends