Question

Two circles x² + y² = 6 and x² + y² – 6x + 8 = 0 are given. Then the equation of the circle through their points of intersection and the point (1, 1) is
(a) x² + y² – 6x + 4 = 0
(b) x² + y² – 3x + 1 = 0
(c) x² + y² – 4y + 2 = 0
(d) none of these

Answer 1

the equation of the circle through their points of intersection and the point (1, 1) is

(c) x^2 + y^2 - 4y + 2 = 0