Two circles x² + y² = 6 and x² + y² – 6x + 8 = 0 are given. Then the equation of the circle through their points of intersection and the point (1, 1) is
(a) x² + y² – 6x + 4 = 0
(b) x² + y² – 3x + 1 = 0
(c) x² + y² – 4y + 2 = 0
(d) none of these
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the equation of the circle through their points of intersection and the point (1, 1) is
(c) x^2 + y^2 - 4y + 2 = 0
devangpradeep01:
do u know the method?
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