two circular coils x and y have the same magnetic induction b the current flowing through the coil xis 3a and through coil y is 5a if the point p is place the centre of both the coils and radius of the coil x is 4cm then the radius of coil y is
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anwer is 6.67 cm
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The radius of coil y is 2.4 cm
Explanation:
The magnetic induction of the coil is:
B = (μ₀nI)/2R
The magnetic induction of the coil x is:
bx = (μ₀n × 3a)/2R
The magnetic induction of the coil y is:
by = (μ₀n × 5a)/(2 × 0.04) = (μ₀n × 5a)/0.08
Now, the magnetic induction of both coils:
bx = by
(μ₀n × 3a)/2R = (μ₀n × 5a)/0.08
3/2R = 5/0.08
R = 3/2 × 0.08/5
∴ R = 0.024 m = 2.4 cm
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