Question

Two closed containers of equal volume filled with air at pressure p not and temperature t not both are connected by a narrow tube if one of the container is maintained at temperature t not and other at temperature t the new pressure in the container will be

Answer 1

just see the uploaded photo.....answer is p=2Po T/T+To

Answer 2

The new pressure in the container will be P = 2P°T/(T+T°)

We know, according to the ideal gas equation,

PV/T = constant, where P is pressure, V is volume of gas, T is the temperature.

So, P₁V₁/T₁    =   P₂V₂/T₂

Given that two closed containers of equal volume filled with air at pressure P°  and temperature T° are connected.

And one container has temperature T° and the other one has T.

Let the final pressure be P.

So, for 2 containers, we have:

P°V/T° + P°V/T° = PV/T° + PV/T

⇒2P°V/T° = PV(1/T° + 1/T)

⇒2P°/T° = P(1/T° + 1/T)

⇒ P = 2P°T/(T+T°)

This is the final pressure.