two coils of resistance 3ohm and 6 ohm connected in series across abattery of 12v find the electrical energy in 1 min which is connected in series
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Answered by
37
Hello dear
we know that
power= energy/time
so
we will find the power first
we know that power = V²/R
so now we will find the Reff.
as they are connected in series then effective resistance= 3+6 = 9ohm.
so now power = 12²/9 = 16.
so power = work done(energy) / time
hence energy= 16× 60. = 960jule
we know that
power= energy/time
so
we will find the power first
we know that power = V²/R
so now we will find the Reff.
as they are connected in series then effective resistance= 3+6 = 9ohm.
so now power = 12²/9 = 16.
so power = work done(energy) / time
hence energy= 16× 60. = 960jule
Answered by
25
hope it will help you
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