Question

Two coils with a coefficient of coupling of 0.6 between them are connected in series as to magnetize
I. in the same direction
ll. in the opposite direction
The corresponding value of equivalent inductance are 1.8H and 0.8H. find the self inductance of the coil and also the mutual inductance between the two coil

Answer 1

Answer:

1. In the same direction

becoz as they are connected in series the direction of current passing through them will remain unchanged. so flux is produced in the same direction

2. Energy stored in the inductor is given by E=1/2(LI^2)

Answer 2

Given: Two coils with a coefficient of coupling of 0.6 between them are connected in series to magnetize

I. in the same direction

ll. in the opposite direction

The corresponding value of equivalent inductance is 1.8H and 0.8H

To Find:  the self-inductance of the coil and also the mutual inductance between the two coil

Solution:

(i) L = L1 + L2 + 2M  

0.6 = L1 + L2 + 2M

and 0.1 = L1 + L2 − 2M

(ii)  (a) From (i) and (ii) we get,

M = 0.125 H  Let L1 = 0.2 H,

then substituting this value in (i) above, we get

L2 = 0.15 H

(b) Coupling coefficient

k = M√(L1L2)

= 0.125/√(0.2 x 0.15)

= 0.72

Therefore, the self-inductance of the coil and also the mutual inductance between the two coils is 0.72.

#SPJ2