Question

Two coin are tossed simmultanously. Find probability of getting
1) at least one tail
2)one head and one tail​

Answer 1

Explanation:

Let us take the experiment of tossing two coins simultaneously:

When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails) i.e., in short (H, H) or (H, T) or (T, T) respectively; where H is denoted for head and T is denoted for tail.

Therefore, total numbers of outcome are 22 = 4

The above explanation will help us to solve the problems on finding the probability of tossing two coins.

Answer 2

Explanation:

1) B = At least 1 tail B = {HT,TH,TT}, n(B) = 3.

P(B) = 34

2) We know that the coin has two sides head (H) and tail (T) So the possible outcomes are Xm. (where x is the number of outcomes when a coin is tossed and m is number of coins) When there are 2 coins

∴ 22= 4 i.e. head and tail ∴ The possible outcomes are HH, HT, TH, TT. Total possible outcomes =4

∴ Chances of getting 1 head and 1 tail = 2, i.e. HT, TH By using the formula, Probability p () = number of favorable outcomes/ total number of outcomes

∴ Probability of getting 1 head and 1tail p (1H 1T) = number of 1head and 1tail/total number of outcomes =2/4 = ½