Two coin are tossed together the find the probality
of getting i two heads ii one head
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To find the probability you have to test it yourself and these both points are correct because if you flip 2 coins their a probability of getting 2 heads,2 tails,1 head 1 tail,1tail 1head
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If two coins are simultaneously tossed, the possible outcomes are (Head, Head), (Head, Tail), (Tail, Head) and (Tail, Tail). Hence n(S) = 4. ... Hence the probability of getting both coins show head = n(E)/ n(S) = 1/4.
Let E6 = event of getting at least 1 head. Then, E6 = {HT, TH, HH} and, therefore, n(E6) = 3. Therefore, P(getting at least 1 head) = P(E6) = n(E6)/n(S) = ¾.
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