Question

two coins are tossed 729 times and outcomes are, no tail: 189, one tail: 297. find the probability of the occurrence of each of these events

Answer 1

p(of getting no tail) = 189/729
p(of getting one tail)=297/729  

Answer 2

Answer:

$\text{Probability(getting no tail)}=\frac{189}{729}$

$\text{Probability(getting one tail)}=\frac{297}{729}$

Step-by-step explanation:

Given : Two coins are tossed 729 times and outcomes are, no tail: 189, one tail: 297.

To find : The probability of the occurrence of each of these events.

Solution :

Total number of outcomes = 729

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

Favorable outcome of no tail = 189

$\text{Probability(getting no tail)}=\frac{189}{729}$

Favorable outcome of one tail = 297

$\text{Probability(getting one tail)}=\frac{297}{729}$