Two coins are tossed simultaneously 1000 times with the following frequencies of different outcomes.
Two heads :210 times
One head :550 times
No head :240 times
Find the probability of occurrence of:-
i)P (two heads + one head)
ii)P (no heads)
Answers
Answered by
34
P(2heads+1heads)=210+550/1000
760/1000=0.760
P(no heads) =240/1000=0.240
760/1000=0.760
P(no heads) =240/1000=0.240
lakhipriyadas1:
Thanks
Answered by
14
1 p ( 2 heads +1head) = 210 +550/1000 = 19 /25
2 p ( no heads ) = 240 /1000 =6/25
2 p ( no heads ) = 240 /1000 =6/25
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