Question

Two coins are tossed simultaneously 1000 times with the following frequencies of different outcomes.
1. Two Heads - 210 times
2. One head - 550 times
3. No head - 240 times

Find the probability of occurrence of each of these outcomes.

Answer 1

just divide each value with 1000
1)210/1000
2)550/1000
3)240/1000
cancel if possible.this should be correct I guess

Answer 2

AnswEr:

→ Let us define the following events :

A = Getting two heads

B = Getting one head

C = Getting no head

We have, Total number of trials = 1000.

________________________

Number of trials in which event A happens : 210

Number of trials in which event B happens : 550

Number of trials in which event C happens : 240

$\therefore$ P(A) = $\sf\frac{Number\:of\:trials\:in\:which\:event\:A\:happens}{Total\:number\:of\:trials}$

= $\tt\frac{210}{1000}=0.21$

P(B) = $\sf\frac{Number\:of\:trials\:in\:which\:event\:B\:happens}{Total\:number\:of\:trials}$

= $\tt\frac{550}{1000}=0.55$

P(C) = $\sf\frac{Number\:of\:trials\:in\:which\:event\:C\:happens}{Total\:number\:of\:trials}$

= $\tt\frac{240}{1000}=0.24$