Question

Two coins are tossed simultaneously 500 times. If we get two heads 100 times ,one head 270 times and no heads 130 times,then find the probability of getting at least one head

Answer 1

here is ur answer..
270/500..=27/50

hope it helps u!!

Answer 2

Answer:

Step-by-step explanation:

LET E1 BE EVENT OF TWO HEADS COMING

LET E2 BE EVENT OF ONE HEAD COMING

LET E3 BE EVENT OF NO HEADS COMING

P(TWO HEADS) =P(E1) =100/500=1/5

P(ONE HEAD) =P(E2) =270/500=27/50

P(NO HEAD) =P(E3)=130/500=13/50

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