Question

Two coins are tossed simultaneously. Find the probability of getting at least one head

Answer 1

Let P(E) be the event of getting at least one head.

Probability=Favorable outcomes/Total Outcomes.

Total outcomes=4=(HT),(HH),(TH),(TT)

Favouravle outcomes=(HT), (HH), (TH) =3

P(E)=3/4

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Answer 2

Sample space= { HH, HT, TH, TT}
n(s) = 4

Event A:- At least one head is seen.
A={ HH, HT, TH}
n(A)=3

$p(a) = \frac{n(a)}{n(s)}$
$= \frac{3}{4}$