Question

Two coins are tossed simultaneously, then the probability of getting exactl one head is a 1/3 b2/6 c1/2 d1/8​

Answer 1

Answer:

$\frac{1}{4}$

Step-by-step explanation:

Given,

Number of coins. 2

Number of conditions. 4

Conditions:;:

1st coin head

1st coin tail

2nd coin head

2nd coin tail

So probability of one head is

$\frac{required \: term}{total \: terms}$

=$\frac{1}{4}$

Answer 2

When two coins are tossed the results are (HH,HT,TH,TT)

Total no. of outcomes =4

1) Exactly one head = only two cases are (HT,TH)

= 4/2

= 2/1

2) At least one tail = There are three cases (HT,TH,TT)

= 4/3

3) No. tail = only one case (HH) = 4/1

4) Atmost one head =three cases (HT,TH,TT)

= 4/3