two coins are tossed simultaneously tossed what is the probability for getting at most one head and getting at least one head
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when the coin are tossed then the probability is :
HHH,HHT,HTH,HTT
TTT,TTH,THT,THH
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Answer: 3/4
Step-by-step explanation:
When two different coins are tossed randomly, the sample space is given by
S = {HH, HT, TH, TT}
Therefore, n(S) = 4.
Let E6 = event of getting at least 1 head. Then,
E6 = {HT, TH, HH} and, therefore, n(E6) = 3.
Therefore, P(getting at least 1 head) = P(E6) = n(E6)/n(S) = ¾.(ans).
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