Two coins are tossed simultaneously two times.If we gets two heads 200 times one heads 100 times and no heads 100 times then find the probability of getting one or more than one head.
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Here, total number of trials = 100 times
Number of heads got (H, H) = 21
∴ P(E) = Number of trials in which two heads occurs/Total number of trials = 21/100
(ii) Total number of trials = 100 times
Number of exactly one head = 55
∴ P(E) = 55/100 = 11/20
(iii) Total number of trials = 100 times
Number of head = 24
∴ Probability = 24/100 = 16/25
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