Two coins are tossed together find probability of atmost one head
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Answered by
1
Answer:
1/2
Step-by-step explanation:
the number of outcomes are - h h ,t t ,h t ,t h =4 where t- tail and h- head
they asked probability of getting one head so..no. of outcomes is 2
so probability = no. of outcomes/ total outcomes = 2/4 = 1/2
Answered by
1
Answer:
S= { HH, HT, TH, TT }
n(S)=4
E= getting at most one head= HT,TH,TT( Because at most one head means that we need only one head or no head at all )
n( E)= 3
Therefore P(E) = n( E )/ n( S ) = 3/4
This is your answer. Hope it helps.
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