Math, asked by savitajaiswar6145, 10 months ago

Two coins are tossed together find probability of atmost one head

Answers

Answered by bhanusreenivasan650
1

Answer:

1/2

Step-by-step explanation:

the number of outcomes are - h h ,t t ,h t ,t h =4  where t- tail and h- head

they asked probability of getting one head so..no. of outcomes  is 2

so probability = no. of outcomes/ total outcomes = 2/4 = 1/2

Answered by getsparkling
1

Answer:

S= { HH, HT, TH, TT }

n(S)=4

E= getting at most one head= HT,TH,TT( Because at most one head means that we need only one head or no head at all )

n( E)= 3

Therefore P(E) = n( E )/ n( S ) = 3/4

This is your answer. Hope it helps.

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