Two coins are tossed together. Find the probability of getting atleast one head
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your answer is 3 by 4
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let sample space be s
s=(HH TH HT TT)
n(s)=4
let a be the event to get atleast 1 head
a=(HH HT TH)
n(a)=3
p(a)= n(a)÷n(s)
p(a)= 3/4
s=(HH TH HT TT)
n(s)=4
let a be the event to get atleast 1 head
a=(HH HT TH)
n(a)=3
p(a)= n(a)÷n(s)
p(a)= 3/4
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