Question

Two coins one tossed siroultaneously. Find the Probability of getting - i)no Tail ii) one head.​

Answer 1

Answer:

(a)

$\frac{1}{4}$

(b)

$\frac{1}{2}$

Step-by-step explanation:

Since the coin is being tossed twice, so the total number of sample spaces will be 4.

S = { (H,H) , (H,T) , (T,H) , (T,T) }

Sample space of no tail -

A = { (H,H) }

=> Number of sample spaces with no tail = 1

Sample space of having only one head -

B = { (T,H) , (H,T) }

=> Number of sample spaces with only one head = 2

Therefore, P(no tail) =

$\frac{1}{4}$

and hence, P(only one head) =

$\frac{2}{4} = \frac{1}{2}$

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