Question

Two coins tossed simultaneously.Find the probability of:-(i)two heads(ii)one head(iii)one tail(iv)at least one head(v)at most one head (only one)(vi)no head.​

Answer 1

Answer:

(1) 1/4

(2) 3/4

(3) 3/4

(4) 3/4

(5) 1/2

(6) 1/4

Answer 2

Answer:

sample space S = [(HH),(HT),(TT),(TH)]

let p (A) be the probability of two heads, >> n (A) = [(HH)]

let p (B) be the probability of one head,  >> n (B) = [(HT),(TH),(HH)]

let p (C) be the probability of one tail,  >> n (C) = [(TT),(HT),(TH)]

let p (D) be the probability of at least one {it means it can be one and more than one} head >> n (D)  =  [(HT),(TH),(HH)]

let p (E) be the probability of at most {it means it can be one not more than one} one head. >> n (E) = [(HT),(TH)]

let p (F) be the probability of no heads,  >> n (F) = [0]

Step-by-step explanation:

hence ,

1.           p (A) = n (A) / n (S)  =>>  1 / 4
2.           p (B) = n (B) / n  (S) =>> 3 / 4
3.          p (C) = n (C) / n (S) =>> 3/4
4.           p (D) = n (D) / n (S) =>> 3 /4
5.          p (E) = n (E) / n (S) =>> 2/4 =>>1/2
6.           p (F) = n (F) / n (S) =>> 1/4

I HOPE IT HELPS.