Question

Two complementary angle differ by 14 degrees find the angle.

Answer 1

Given:

• Two complementary angles differ by 14°

Find:

• What are angles

Solution:

Let, Smaller angle = x

Largest Angle = x + 14

we, know that

Sum of complementary angles is 90°

So,

$\sf \dashrightarrow x + x + 14= {90}^{ \circ}$

$\sf \dashrightarrow 2x + 14 = {90}^{ \circ}$

$\sf \dashrightarrow 2x= {90}^{ \circ} - {14}^{ \circ}$

$\sf \dashrightarrow 2x= {76}^{ \circ}$

$\sf \dashrightarrow x= \dfrac{76}{2}$

$\sf \dashrightarrow x= {38}^{ \circ}$

$\bold{ \therefore x= {38}^{ \circ}}$

______________________________

So, Smaller Angle = x = 38°

Larger Angle = x + 14 = 38 + 14 = 52°