two complementary angles differ by 10 degree the larger angle is
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Let the first angle be x.
According to Question,
Second angle = x - 10
∵ ∠1 + ∠2= 90
∴x + x - 10 = 90
⇒ 2x = 100
x = 50
First ∠le = 50°
Second∠le = x-10°=50-10=40°
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