Math, asked by ksasi129, 1 year ago

two complementary angles differ by 12°,find the angles

Answers

Answered by rahulfrenzi70
137

Let the angle be x.
Then its complementary angle=(90-x)
A/Q
(90-x)-x=12
=› 90-x-x =12
=› 90-2x =12
=› 90-12 =2x
=› 78. =2x
=› x=78/2=39
=› x=39
Hence angles =39 ans
and (90-39)
=51.ans

Answered by pulakmath007
9

The angles are 51° & 39°

Given :

Two complementary angles differ by 12°

To find :

The angles

Solution :

Step 1 of 2 :

Form the equation

Here it is given that two complementary angles differ by 12°

Let the angles are x and x + 12°

By the given condition

x + ( x + 12° ) = 90°

Step 2 of 2 :

Find the angles

x + ( x + 12° ) = 90°

⇒ 2x + 12° = 90°

⇒ 2x = 90° - 12°

⇒ 2x = 78°

⇒ x = 39°

So the angles are 51° & 39°

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