Two complementry angles differ by 10°.find the angle [hint:sum of two complementary angles is 90° ]
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let one angle be x°
and other be y°
therefore x+y =90°(since the angles are complementary)
x-y=10°(given)
adding both equations
x+y+x-y = 90+10
2x = 100
x=50°
therefore y = 90-50 = 40°
and other be y°
therefore x+y =90°(since the angles are complementary)
x-y=10°(given)
adding both equations
x+y+x-y = 90+10
2x = 100
x=50°
therefore y = 90-50 = 40°
yash73686436:
sahi hai
hmm thanks
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