two complementry angles differ by 12 degrees ,find the angles
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Answered by
15
let one angle to be x then other will be x-12
=x+x-12=90°
=2x-12=90°
=2x=102°
=x=102/2
=therefore angles are 51° and 39°
=x+x-12=90°
=2x-12=90°
=2x=102°
=x=102/2
=therefore angles are 51° and 39°
Answered by
13
sum of any two angles equals to 90 degrees is called complementary angles
if one angle =x
second angle =90-x
difference =12
x-(90-x) =12
x-90+x =12
2x-90=12
2x=12+90
2x=102
x=102/2
x=51
therefore
two angles are ,51 and (90-51)=39
if one angle =x
second angle =90-x
difference =12
x-(90-x) =12
x-90+x =12
2x-90=12
2x=12+90
2x=102
x=102/2
x=51
therefore
two angles are ,51 and (90-51)=39
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