Question

Two compounds ’A’ and ’B’ have the same molecular formula C3H6O2. One of them reacts with sodium metal and NaHCO3 to liberate H2 gas and a gas ’C', respectively. ’C' turns lime water milky. The other compound does not react with either Na metal or NaHCO3 but undergoes saponification to give sodium salt of a carboxylic acid and wood spirit, 'D’. Identify A, B, C and D.

Answer 1

Explanation:

5x54x6yx.y6x4624..y55555555x54x6yx.y6x4624..y5555555

Answer 2

Answer:

• A is propanoic acid
• B is methyl acetate  
• C is carbon dioxide
• D is methanol

Explanation:

The molecular formula is  C3H6O2 .

A and B has a molecular formula C3H6O2

Two possible compounds with molecular formula C3H6O2 are propanoic acid (CH3CH2COOH) and methyl acetate (CH3COOCH3).

one of the compound reacts with NaHCO3 and forms co2

CH3CH2COOH + NaHCO3 →→→ CH3CH2COONa + H2O + CO2

Carbon dioxide gas turns lime water milky . The reaction will be :

Ca(OH)2 + CO2 →→CaCO3 + H2O

so compound Is CH3CH2COOH

Methyl acetate on saponification gives sodium acetate and wood spirit i.e., methanol.

CH3COOCH3 + NaOH →→→CH3COONa + CH3OH  

so,

• A is propanoic acid
• B is methyl acetate  
• C is carbon dioxide
• D is methanol