Question

Two compounds X and Y have the same molecular formula C2H4O2 . One of them reacts with sodium metal to liberate H2 and CO2 with NaHCO3. Second one doesnt react with Na metal and NaHCO3 but undergoes hydrolysis with NaOH to form salt of carboxylic acid and compound Z which is called woo dspirit. Identify X,Y and Z and write the chemical equations for the reactions involved.

Answer 1

Let X be acetic acid.[CH3COOH]
Acetic acid reacts with sodium to liberate H2
the reaction is as follows:
CH3COOH +Na -----> CH3COONa +H2
It reacts with NaHCO3 to liberate CO2
The reaction is as follows:
CH3COOH +NaHCO3 ----> CH3COONa+ CO2
Element Y undergoes Hydrolysis with NaoH to form Carboxylic acid salt . It means Y is an Ester.[Methyl Methanoate.]
The reaction is as follows:
HCOOCH3+ NaOH---->HCOONa +CH3OH
Therefore, Compound Z is Methanol

Answer 2

Let us assume that compound X reacts with sodium metal to liberate H2 and CO2.

•°•X is a acetic acid (CH3COOH)

Acetic acid reacts with sodium to liberate H2

The reaction is as follows:

CH3COOH+Na-->CH3COONa+H2

It reacts with NaHCO3 to liberate CO2

The reaction is as follows:

CH3COOH+NaHCO3-->CH3COONa+CO2

Element Y undergoes hydrolysis with NaOH to form salt of carboxylic acid. It means Y is an ester,Methyl methanoate

The reaction is as follows:

HCOOCH3+NaOH-->HCOONa+CH3OH

•°• Compound Z is methanol.