Question

Two concave lens each of focal length 60 CM are placed in contact with each other find the power of the combination

Answer 1

Answer:

( -3.334 )dioptre

Explanation:

according to power

p= 1/F1+ 1/F2

p= 100/(-60) + 100/(-60)

p=200/(-60)

p=20/(-6)

p=10/(-3)

p=(-3.33 )dioptre

Answer 2

The power of the combination is (-3.34 D).

Explanation:

Given that,

Focal length of each of the lens, $f_1=f_2=-60\ cm=-0.6\ m$

The focal length of the combination is given by :

$\dfrac{1}{f}=\dfrac{1}{f_1}+\dfrac{1}{f_2}$

$\dfrac{1}{f}=\dfrac{1}{(-0.6)}+\dfrac{1}{(-0.6)}$

f = -0.3 m

Power is given by :

$P=\dfrac{1}{f}$

$P=\dfrac{1}{-0.3}$

P = -3.34 D

So, the power of the combination is (-3.34 D). Hence, this is the required solution.

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