Two concentric circles are of radii 6.5cm
And 2.5cm.find the length of the chord of the larger circle which touches the smaller circle.
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Answered by
0
Answer:
Step-by-step explanation:
We know that the radius and tangent are perpendicular at their point of contact
In right triangle AOP
Since, the perpendicular drawn from the center bisects the chord.
PA = PB = 6 cm
Now, AB = AP + PB = 6 + 6 = 12 cm
Hence, the length of the chord of the larger circle is 12 cm.
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Answered by
2
Answer:
Step-by-step explanation:
PA = PB = 6 cm
Now, AB = AP + PB = 6 + 6 = 12 cm
Hence, the length of the chord of the larger circle is 12 cm.
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