Two concentric circles with centre o and radius 5 cm and 3 cm from an external point p two tangents pa and pb are drawn to the circle respectively if be equal to 12 cm then find length of pb
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InΔOAP is a right angle at A then OP2 = OA2 + AP2
OA = 5 cm, OB = 3 cm and AP = 12 cm
OP2 = 52 + 122 = 25 + 144 = 169
OP = 13 cm
In ΔOBP is a right angle at A then OP2 = OB2 + BP2
169 = 9 + BP2
BP2= 160
BP = 4√10 cm.
∴ length of BP = 4√10 cm.
OA = 5 cm, OB = 3 cm and AP = 12 cm
OP2 = 52 + 122 = 25 + 144 = 169
OP = 13 cm
In ΔOBP is a right angle at A then OP2 = OB2 + BP2
169 = 9 + BP2
BP2= 160
BP = 4√10 cm.
∴ length of BP = 4√10 cm.
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