two concurrent forces 15N and 17N acting at an angle of 45 with respect to each other calculate the magnitude and direction of the Resultant force
Answers
Answer:
Let, P and Q be the two forces having magnitudes 15 Newtons and 20 Newtons respectively. They are acting at an angle α = 60°.
Let, R be the resultant vector. Vector R acts at an angle θ with vector P.
So, |R^2| = 15^2 + 20^2 + 2 * 15 * 20 * cos 60°
Or, |R^2| = 225 + 400 + 300 = 925
Or, |R| = 30.4138 Newtons
So, tan θ = (20 * sin 60°) / {15 + 20 * cos 60°}
Or, tan θ = (10√3) / (15 + 10) = (10√3) / 25
Or, tan θ = (2√3) / 5 = 0.69282
Or, θ = 34.715°
So, magnitude of the resultant force = 30.4138 Newtons and the resultant force acts at an angle 34.715° with the 15 Newton magnitude force.
Explanation:
Hope it helps
Answer:
Two forces that act in opposite directions produce a resultant force that is smaller than either individual force. To find the resultant force subtract the magnitude of the smaller force from the magnitude of the larger force. The direction of the resultant force is in the same direction as the larger force.