two condensers of capacity 2F and 3F are connected in series,a third condenser of 1F is connected in parallel to them,the resultant capacity in Farad(F) will be______
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◆ Answer -
Resultant capacity = 11/5 F
● Explaination -
Let's solve this step-by-step.
# Given -
C1 = 2F
C2 = 3F
C3 = 1 F
# Solution
When 2F & 3F condensers are connected in series -
1/C = 1/C1 + 1/C2
1/C = 1/2 + 1/3
C = 6/5 F
When this 6/5 F condenser is connected in parallel to 1 F condenser,
C' = C + C3
C' = 6/5 + 1
C' = 11/5 F
Therefore, resultant capacity of the combination is 11/5 F.
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