Question

Two conducting spheres of radii 2 cm and 4 cm have equal surface charge density find the ratio of electric potential on the surface

Answer 1

Explanation:

Given Two conducting spheres of radii 2 cm and 4 cm have equal surface charge density find the ratio of electric potential on the surface

• Now we have σ = Q / A
• Also given ratio of radii r1 : r2 = 2 : 4
•                                                     = 1 : 2
• Now we have A1 : A2 = 4πr1^2 : 4πr2^2
•                                      = r1^2 : r2^2
• So we get the ratio as A1 : A2 = 1 : 4
• Then σ1 : σ2 = Q / A1 : Q / A2
• So we get A2 : A1
•              = 4 : 1

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