Question

Two cones have their base radius in ratio of 3:1 and the ratio of their heights as 1:3. Find the ratio of their volume.
​

Answer 1

Answer:

Given h

1

:h

2

=1:3,r

1

:r

2

=3:1

h

1

=x,h

2

=3x,r

1

=3y,r

2

=y

V

2

V

1

=

(1/3)πr

2

2

h

2

(1/3)πr

1

2

h

1

=

y

3

×3x

y

2

×3x

=

1

3

'

Answer 2

$\huge\underline\mathfrak\red{✨ Answer✨}$

$V2V1=(1/3)πr22h2(1/3)πr12h1=y3×3xy2×3x=13$