Two consecutive even integers have a sum of 42 the integers
Answers
let integer is x, x+2,
x+x+2=42
3x+2=42
2x=42-2
2x=40
x=40÷2
x=20
so integer are 20,22....
The two consecutive even integers have a sum of 42 is 10 and 12 when the consecutive integers are x and x+2
Given that,
We have to find the two consecutive even integers have a sum of 42.
We know that,
What is consecutive number?
Numbers that follow one another in order, from the smallest to the greatest, are referred to as consecutive numbers. Every time there are two numbers, there is typically a difference of 1. Keep in mind that every predecessor-successor combination has a fixed difference.
So,
The two consecutive even integers are x and x+2,
Sum is 42 that is
x+x+2 = 42
2x+2 =42
2x=42-2
2x=40
x=10
So,
x=10
x+2=12
Therefore, The two consecutive even integers have a sum of 42 is 10 and 12 when the consecutive integers are x and x+2
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