Question

two consecutive even number are such that half of larger number exceeds one forth of smaller number by 5 . find larger no.

Answer 1

Hey buddy ❤️❤️

Answer:

❤️❤️

LET ,1st consecutive even no. = x + 2

LET ,2nd consecutive even no. = x + 4

according to problem ,

=> (x + 4)/2 =(x + 2)/4 + 5

=> (x + 4)/2 = (x + 2 + 20)/4

=> (x + 4) = (x + 22)/2

=> 2x + 8 = x + 22

=> x = 14

So,

1st consecutive even no = 16

2nd consecutive even no = 18

∴ The larger number = 18

Hope it helps you ✌️✌️❤️

Answer 2

let the smaller no. be x

then larger no.=x+2

Now,A/Q

1/2(x+2)+5=1/4x

therefore x=24

x+2=26