Two consecutive even numbers are such that half of the larger number exceeds one-forth of the smaller number by 5. Find the larger number.
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2n 2n+2 are even numbers
half of larger = 2n+2/2
1/4 of small=2n/4
2n+2 /2 = 2n/4 +5
2n+2/2 -2n/4 =5
2(2n+2) -2n/4 =5
4n+4-2n/4 =5
2n+4 =5×4
2n+4=20
2n=20-4
2n=16
n=16/2
n=8
larger number
2n+2
2(8)+2
16+2
18 is answer
half of larger = 2n+2/2
1/4 of small=2n/4
2n+2 /2 = 2n/4 +5
2n+2/2 -2n/4 =5
2(2n+2) -2n/4 =5
4n+4-2n/4 =5
2n+4 =5×4
2n+4=20
2n=20-4
2n=16
n=16/2
n=8
larger number
2n+2
2(8)+2
16+2
18 is answer
naveen8453:
Can you solve it more nicely in a page
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