two consecutive numbers in which the sum of 3 times the first number and the square of second number is 85.find the number
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from the quadratic equation:
x+12=0
x=-12
x-7=0
x=7
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Two consecutive numbers are (-12 and -11) or ( 7 and 8)
Step-by-step explanation:
- Given that
First number = X
Second number = X +1
- Here it is given that the sum of 3 times the first number and the square of second number is 85. Means
3×First number + (second number)² =85
- 3×X + (X +1)² =85
3X + X² + 2X + 1 =85
X² + 5X + 1 =85
X² + 5X + 1 - 85 =0
X² + 5X - 84 =0
- By middle term splitting method
X² + 12X -7X - 84 =0
X( X+12) -7(X +12) =0
(X+12 ) (X -7) = 0
- So
X + 12 = 0 or X - 7 = 0
X = -12 or X = 7
- If X = -12
First number = X = -12
Second number = X +1 = -12 +1 = -11
- If X = 7
First number = X = 7
Second number = X +1 = 7 +1 = 8
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