two consecutive vertices of a rectangle of area tens unit square are ( 1, 3 )and (- 2, - 1 )
other two vertices are
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AB=√(1+2)2+(3+1)2
=√9+16
=√25
=5unit
hence,AB=DC=L=5unit
Area of rectangle =L×B
10=5×B
B=10/5
B=2unit
hence L=5unit
B=2unit
=√9+16
=√25
=5unit
hence,AB=DC=L=5unit
Area of rectangle =L×B
10=5×B
B=10/5
B=2unit
hence L=5unit
B=2unit
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